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      },
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        "ocr_text": "<> e   ] > volterracinfoitcrmsitsskeimincammino2idascription      .   940 EI"
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      {
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        "visible_output_snippet": " Problerma  Ouipur - DebugCorsole  Terminel  Ports      () bah-cemtts + + D ®     X\n  [enricoparchlinux paletta]$ g++ paletta.cpp grader.cpp -o paletta\n               from fusrsincludesc++/16/x86_64-pc-linux-gnusbitssstdc++ . h:53,\n               from paletta.cpp:1:\n tusr/includesc++/16/bitssst] vector.h:468:11: note:   ‘std::vector'\n   ace |    class vector : protected _Vector_base<_Tp, _Alloc>\n      |      P\n tusr/include/c++/16/vector:97:13: note:   ‘std::per: :vector'\n    57 |      using vector = std: :vector<_Tp, polyrorphic_allocator<_Tp>>;\n      |      o\n tusr/include/c++/16/bits/stl_vector.h:468:11: note:   'std::vector\n   ace |    class vector : protected _Vector_base<_Tp, _Alloc>\n      |      o\n paletta.cpp:9:16: exzor: expected primary-expression before 'int'\n     5|      vectorednt> ft{N * 2 + 2, B);\n      |      peee\n® [enricoparchlinux paletta]s pal:m];El g++ paletta.cpp grader.cpp -o paletta      \\\n° [enricoarchlinux"
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      {
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        "ocr_text": "peletta > T rputtt\n     1   6\n     2230541      -"
      },
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        "ocr_text": " Problerma  Ouipur - DebugCorsole  Terminel  Ports      () bah-cemtts + + D ®     X\n  [enricoparchlinux paletta]$ g++ paletta.cpp grader.cpp -o paletta\n               from fusrsincludesc++/16/x86_64-pc-linux-gnusbitssstdc++ . h:53,\n               from paletta.cpp:1:\n tusr/includesc++/16/bitssst] vector.h:468:11: note:   ‘std::vector'\n   ace |    class vector : protected _Vector_base<_Tp, _Alloc>\n      |      P\n tusr/include/c++/16/vector:97:13: note:   ‘std::per: :vector'\n    57 |      using vector = std: :vector<_Tp, polyrorphic_allocator<_Tp>>;\n      |      o\n tusr/include/c++/16/bits/stl_vector.h:468:11: note:   'std::vector\n   ace |    class vector : protected _Vector_base<_Tp, _Alloc>\n      |      o\n paletta.cpp:9:16: exzor: expected primary-expression before 'int'\n     5|      vectorednt> ft{N * 2 + 2, B);\n      |      peee\n® [enricoparchlinux paletta]s pal:m];El g++ paletta.cpp grader.cpp -o paletta      \\\n° [enricoarchlinux"
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        "ocr_text": " Protieria  Outpur  DebugCornsola  Terminel  Ports      () banh-sestta + - D ®     ux\n  [enrico@srchlinux paletta]$ g++ paletta.cpp grader.cpp -o paletta\n    57 |      using vector = std::vector<_Tp, polyrorphic_allocator<_Tp>>;\n       |      i\n  tusr/include/c++/16/bits/stl vector.h:468:11: note:   ‘std::vector'\n   ace |    class vector : protected _Vector_base<_Tp, _Alloc>\n       |      pesims\n  paletta.cpp:9:16: ervor: expected privary-expression before 'inf\n     5|      vectorednt> ft[N * 2+ 2, B);\n       |      e\n® [enricoBarchlinux paletta]s ge+ paletta.cpp grader.cpp -o paletta\n® [enricoBarchlinux paletta]s ./paletta\n  sC\n® [enricoparchlinux paletta]$ g++ paletta.cpp grader.cpp -o paletta\n® [enricoparchlinux paletta]5 ./paletta\n® [enricoBarchlinux paletta]$ g++ paletta.cpp grader.cpp -o paletta\n® [enricoBarchlinux paletta]s - /paletta\n* [enricosarchlinux paletta]s |"
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        "ocr_text": "          punteggio:      -\n             e  1: se riporti correttamente il numero minimo di ribaltamenti;\n             e  (.2:  se il vettore V & ordinabile e restituisci un numero maggiore o uguale a () (anche se non\n               corrisponde  al numero minimo  di ribaltamenti),  cioè  riesci a distinguere quando il  vettore è\n               ordinabile;\n             e  0: altrimenti.\n          Per ogni subtask riceverai un punteggio pari al valore del subtask moltiplicato per il peggior punteggio\n          ottenuto su uno dei suoi test case,\n             .  Subtask 1  [ 5 punti]: Casi d'esempio.\n             «  Subtask 2  [19 punti]: N < 100.\n             «  Subtask 3  [24 punti]: N < 5000.\n             .  Subtask 4  [21 punti]: N < 100000 e R < 100 (oppure V non & ordinabile).\n             «  Subtask 5  [25 punti]: N < 100000.\n             .  Subtask 6  [ 6 punti]: Nessuna limitazione specifica.\n          Esempi di input/output\n         —  +———1\n          Spiegazione\n          Nel primo caso di esempio, non è possibile ordinare il vettore dato.\n          Nel secondo caso di esempio, la soluzione proposta produce la seguente sequenza di ribaltamenti:\n                                —      )\n                                |      d\n—  ,"
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        "ocr_text": "               ara  di   selezione    Stage   2ZUZ0      K\n            Volterra, 08 novembre 2026      mincammino2 e  IT\n             Cammino  minimo  (mincammino2)\n|\n            Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n            minimo dal nodo 0 ad ogni nodo.\n             Implementazione\n            Dovrai sottoporre un unico file, con estensione .cpp.\n                 ¥ Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                     implementazione.\n            Dovrai implementare la seguente funzione:\n                e  L'intero N rappresenta il numero di nodi del grafo.\n                e  L'intero M rappresenta il numero di archi del grafo.\n                e  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                  il nodo di arrivo e il peso di ogni arco.\n                .  La funzione dovrà popolare I'array D, dove, per ogni i = 0... N —1, il valore D; dovra essere uguale\n                  alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n                  0, D; dovra essere —1.\n            Grader di prova\n            Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n            la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n            da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n            11 file di input & composto da M + 1 righe, contenenti:\n                e  Riga 1: gli interi N e M.\n                e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n            11 file di output & composto da un’unica riga, contenente gli N interi Do, Dy,..., Dx-1.\n            Assunzioni\n   ———      i ii    ii |"
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        "ocr_text": "               ara  di   selezione    Stage   2ZUZ0      K\n            Volterra, 08 novembre 2026      mincammino2 e  IT\n             Cammino  minimo  (mincammino2)\n|      Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n|      minimo dal nodo 0 ad ogni nodo.\n             Implementazione\n            Dovrai sottoporre un unico file, con estensione .cpp.\n                 ¥ Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                     implementazione.\n            Dovrai implementare la seguente funzione:\n                e  L'intero N rappresenta il numero di nodi del grafo.\n                e  L'intero M rappresenta il numero di archi del grafo.\n                e  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                  il nodo di arrivo e il peso di ogni arco.\n                .  La funzione dovra popolare l’array D, dove, per ogni i = 0... N —1, il valore D; dovrà essere uguale\n                  alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n                  0, D; dovra essere —1.\n            Grader di prova\n            Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n            la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n            da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n            11 file di input & composto da M + 1 righe, contenenti:\n                e  Riga 1: gli interi N e M.\n                e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n            11 file di output & composto da un’unica riga, contenente gli N interi Do, Dy,..., Dx-1.\n            Assunzioni\n   —      ii     ii      ii      ii |"
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        "ocr_text": "               ara  di   selezione    Stage   2ZUZ0      K\n            Volterra, 08 novembre 2026      mincammino2 e  IT\n             Cammino  minimo  (mincammino2)\n|      Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n            minimo dal nodo 0 ad ogni nodo.\n             Implementazione\n            Dovrai sottoporre un unico file, con estensione .cpp.\n                 ¥ Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                     implementazione.\n            Dovrai implementare la seguente funzione:\n                e  L'intero N rappresenta il numero di nodi del grafo.\n                e  L'intero M rappresenta il numero di archi del grafo.\n                e  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                  il nodo di arrivo e il peso di ogni arco.\n                .  La funzione dovra popolare l’array D, dove, per ogni i = 0... N —1, il valore D; dovrà essere uguale\n                  alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n                  0, D; dovra essere —1.\n            Grader di prova\n            Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n            la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n            da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n            11 file di input & composto da M + 1 righe, contenenti:\n                e  Riga 1: gli interi N e M.\n                e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n            11 file di output & composto da un’unica riga, contenente gli N interi Do, Dy,..., Dx-1.\n            Assunzioni\n   ———      i ii    ii |"
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        "text_content": "#include <vector>\n#include <algorithm>\n#include  <bits/stdc++ h>\nusing namespace std;\nvoid mincammino(int N,  int M,  vector<int> X,  vector<int> ¥,  vector<int> P,  vector<long long>&\n    vector<vector<pair<int,  int>>> adj(N);\n    for (int i = 0;  1 < M;  i++)\n    {\n        adj [X[1]].push_back({¥[1],  PIi]});\n    }\n    priority_queue<pair<long long,  int>> pq;\n    vector<int> distanze(N,  LLONG_MAX);\n    distanze[®]  = 0;\n    Pq.push({®,  8});\n    whilefl\nì",
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        "ocr_text": "#include <vector>\n#include <algorithm>\n#include  <bits/stdc++ h>\nusing namespace std;\nvoid mincammino(int N,  int M,  vector<int> X,  vector<int> ¥,  vector<int> P,  vector<long long>&\n    vector<vector<pair<int,  int>>> adj(N);\n    for (int i = 0;  1 < M;  i++)\n    {\n        adj [X[1]].push_back({¥[1],  PIi]});\n    }\n    priority_queue<pair<long long,  int>> pq;\n    vector<int> distanze(N,  LLONG_MAX);\n    distanze[®]  = 0;\n    Pq.push({®,  8});\n    whilefl\nì"
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        "ocr_text": "               ara  di   selezione    Stage   2ZUZ0      K\n            Volterra, 08 novembre 2026      mincammino2 e  IT\n             Cammino  minimo  (mincammino2)\n|      Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n            minimo dal nodo 0 ad ogni nodo.\n             Implementazione\n            Dovrai sottoporre un unico file, con estensione .cpp.\n                 ¥ Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                     implementazione.\n            Dovrai implementare la seguente funzione:\n                e  L'intero N rappresenta il numero di nodi del grafo.\n                e  L'intero M rappresenta il numero di archi del grafo.\n                e  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                  il nodo di arrivo e il peso di ogni arco.\n                .  La funzione dovra popolare l’array D, dove, per ogni i = 0... N —1, il valore D; dovra essere uguale\n                  alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n                  0, D; dovra essere —1.\n            Grader di prova\n            Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n            la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n            da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n            11 file di input & composto da M + 1 righe, contenenti:\n                e  Riga 1: gli interi N e M.\n                e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n            11 file di output & composto da un’unica riga, contenente gli N interi Do, Dy,..., Dx-1.\n            Assunzioni\n   —      ii i_i ii      |"
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        "ocr_text": "               ara  di   selezione    Stage   2ZUZ0      K\n            Volterra, 08 novembre 2026      mincammino2 e  IT\n             Cammino  minimo  (mincammino?2)\n            Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n            minimo dal nodo 0 ad ogni nodo.\n|      Implementazione .\n            Dovrai sottoporre un unico file, con estensione .cpp.\n                 U Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                     implementazione.\n            Dovrai implementare la seguente funzione:\n                e  L'intero N rappresenta il numero di nodi del grafo.\n                e  L'intero M rappresenta il numero di archi del grafo.\n                e  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                  il nodo di arrivo e il peso di ogni arco.\n                «  La funzione dovra popolare l’array D, dove, per ogni i = 0... N —1, il valore D; dovra essere uguale\n                  alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n                  0, D; dovrà essere —1,\n            Grader di prova\n            Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n            la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n            da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n            11 file di input & composto da M + 1 righe, contenenti:\n                e  Riga 1: gli interi N e M.\n                e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n            11 file di output & composto da un’unica riga, contenente gli N interi Do, Dy,..., Dx-1.\n            Assunzioni\n   ———      ii      g ii      ii |"
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        "ocr_text": "#include <vector>\n#include <algorithm>\n#include <bits/stdc++.h>\nusing namespace std;\nvoid mincammino(int N,  int M,  vector<int> X,  vector<int> Y,  vector<int> P,  vector\n|    vector<vector<pair<int,  int>>> adj(N);\n    for  (int i = 0;  i < M;  i++)\n     {\n         adj (X[1]].push_back({Y[i],  P[i]});\n     }\n    priority_queue<pair<long long,  int>> pg;\n    |\n    pg.push({0,  0});\n    while(!pg.empty())  {\n         int top = pq.top().second;\n         pq.pop();\n         for(auto  [i,  w]  :  adj[top])  {\n             distanze\n         }\n     }\n}"
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        "ocr_text": "            ara  di   selezione    Stage   2ZUZ0      K\n          Volterra, 08 novembre 2026      mincammino2 e  IT\n           Cammino  minimo  (mincammino?2)\n          Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n          minimo dal nodo 0 ad ogni nodo.\n          Implementazione\n          Dovrai sottoporre un unico file, con estensione .cpp.\n              U Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                  implementazione.\n          Dovrai implementare la seguente funzione:\n             e  L'intero N rappresenta il numero di nodi del grafo.\n             e  L'intero M rappresenta il numero di archi del grafo.\n             o  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                il nodo di arrivo e il peso di ogni arco.\n             «  La funzione dovra popolare l’array D, dove, per ogni i = 0... N —1, il valore D; dovra essere uguale\n               alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n               0, D; dovrà essere —1,\n          Grader di prova\n          Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n          la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n          da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n          11 file di input & composto da M + 1 righe, contenenti:\n             e  Riga 1: gli interi N e M.\n             e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n          11 file di output & composto da un’unica riga, contenente gli N interi Do, Dy,..., Dx-1.\n          Assunzioni\n———      i ii    ii |"
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        "text_content": "#include <vector>\n#include <algorithm>\n#include <bits/stdc++.h>\nusing namespace std;\nvoid mincammino(int N,  int M,  vector<int> X,  vector<int> Y,  vector<int> P,  vector\n|    vector<vector<pair<int,  int>>> adj(N);\n    for  (int i = 0;  i < M;  i++)\n     {\n         adj (X[1]].push_back({Y[i],  P[i]});\n     }\n    priority_queue<pair<long long,  int>> pg;\n    vector<bool> visti  (N,  0);\n    pq.push({0,  0});\n    while(!pq.empty())  {\n         int top = pq.top().second;\n         pq.pop();\n         for(auto  [i,  w]  :  adj[top])  {\n             distanze\n         }\n     }\n}",
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        "ocr_text": "#include <vector>\n#include <algorithm>\n#include <bits/stdc++.h>\nusing namespace std;\nvoid mincammino(int N,  int M,  vector<int> X,  vector<int> Y,  vector<int> P,  vector\n|    vector<vector<pair<int,  int>>> adj(N);\n    for  (int i = 0;  i < M;  i++)\n     {\n         adj (X[1]].push_back({Y[i],  P[i]});\n     }\n    priority_queue<pair<long long,  int>> pg;\n    vector<bool> visti  (N,  0);\n    pq.push({0,  0});\n    while(!pq.empty())  {\n         int top = pq.top().second;\n         pq.pop();\n         for(auto  [i,  w]  :  adj[top])  {\n             distanze\n         }\n     }\n}"
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        "ocr_text": "            ara  di   selezione    Stage   2ZUZ0      K\n          Volterra, 08 novembre 2026      mincammino2 e  IT\n           Cammino  minimo  (mincammino?2)\n          Dato un grafo pesato diretto con N nodi indicizzati da 0 a N — 1, trovare la lunghezza del cammino\n          minimo dal nodo 0 ad ogni nodo.\n          Implementazione\n          Dovrai sottoporre un unico file, con estensione .cpp.\n              U Tra  gli allegati a questo task  troverai  un  template mincammino.cpp con  un esempio di\n                  implementazione.\n          Dovrai implementare la seguente funzione:\n             e  L'intero N rappresenta il numero di nodi del grafo.\n             e  L'intero M rappresenta il numero di archi del grafo.\n             e  Gli array X, Y e P, indicizzati da 0 a M — 1, rappresentano rispettivamente il nodo di partenza,\n                il nodo di arrivo e il peso di ogni arco.\n             «  La funzione dovra popolare l’array D, dove, per ogni i = 0... N —1, il valore D; dovra essere uguale\n               alla lunghezza del cammino minimo dal nodo 0 al nodo i. Se il nodo i non & raggiungibile dal nodo\n               0, D; dovrà essere —1,\n          Grader di prova\n          Nella directory relativa a questo problema è presente una versione semplificata del grader usato durante\n          la correzione, che potete usare per testare le vostre soluzioni in locale.  Il grader di esempio legge i dati\n          da stdin, chiama le funzioni che dovete implementare e scrive su stdout, secondo il seguente formato.\n          11 file di input & composto da M + 1 righe, contenenti:\n             e  Riga 1: gli interi N e M.\n             e  Riga2+iperi=0...M — 1: gliinteri X;, Y e P,.\n          11 file di output è composto da un'’unica riga, contenente gli N interi Do, Di,..., Dx-1.\n          Assunzioni\n———      i ii    ii |"
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        "ocr_text": " Potiena  Outpur Debug Console  Terminei  Ports      ©) spateta-contia + + D) D     ux\n® [enricoparchlinux paletta]$ g++ paletta.cpp grader.cpp -o paletta\n® [enricoparchlinux paletta]s ./paletta"
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        "ocr_text": "=  puetinrpor      212  |-  %%  +| O0 d | è | s  e      J‘ggl"
      },
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        "box_2d": [
          496,
          126,
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        "ocr_text": "   «  Subtask 3  [24 punti]: N < 5000.\n   .  Subtask 4  [21 punti]: N < 100000 e R < 100 (oppure V non è ordinabile).\n   «  Subtask 5  [25 punti]: N < 100000.\n   .  Subtask 6  [ 6 punti]: Nessuna limitazione specifica.\nEsempi di input/output\n 5      -1\n 20431\n 6      3\n 230541\nSpiegazione\nNel primo caso di esempio, non è possibile ordinare il vettore dato,\nNel secondo caso di esempio, la soluzione proposta produce la seguente sequenza di ribaltamenti:\n paletta      Pagina 2 di 2      |"
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        "ocr_text": " Potiena  Ouipur Debug Corsole  Terminei  Ports      ©) pateta-contia + + D) D     ux\n® [enricogarchlinux paletta]$ ./paletta"
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        "ocr_text": "   «  Subtask 3  [24 punti]: N < 5000.\n   .  Subtask 4  [21 punti]: N < 100000 e R < 100 (oppure V non è ordinabile).\n   «  Subtask 5  [25 punti]: N < 100000.\n   .  Subtask 6  [ 6 punti]: Nessuna limitazione specifica.\nEsempi di input/output\n 5      -1\n 20431\n 6      3\n 230541\nSpiegazione\nNel primo caso di esempio, non è possibile ordinare il vettore dato,\nNel secondo caso di esempio, la soluzione proposta produce la seguente sequenza di ribaltamenti:\n paletta      Pagina 2 di 2      |"
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        "ocr_text": "             +  Subtask 1   [ 0 punti]: Casi d’esempio.\n             «  Subtask 2  [20 punti]: M = N — 1 ed è possibile raggiunere ogni nodo partendo dal nodo 0.\n             +  Subtask 3  [20 punti]: P[i] = 1.\n             +  Subtask 4   [30 punti]: N < 1000 e M < 3000.\n             «  Subtask 5  [30 punti]: Nessuna limitazione aggiuntiva\n          Esempi di input/output\n          f      atdin      T      atdont      |      L\nj"
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