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          "e a aÀ\nScarica il testo del problema",
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        "ocr_text": "evento gli ha ispirato l’idea del paletta-sort, una nuova interessante procedura di ordinamento.\nDato un vettore V contenente gli interi da 0 a  N —1  (indicizzato da 0 a N —1), l’unica operazione ammessa\nnel paletta-sort è l’operazione ribalta. Questa operazione sostituisce tre elementi A, B, C' consecutivi di\nV con i corrispondenti ribaltati C, B, A. Aiuta Romeo a capire se è possibile ordinare il vettore V, e in\ncaso affermativo quante e quali operazioni ribalta sono sufficienti!\nImplementazione\nDovrai sottoporre esattamente un file con estensione .cpp.\n    & Tra gli  allegati  a questo  task  troverai  un  template  (paletta.cpp)  con  un esempio  di\n        implementazione.\nDovrai implementare la seguente funzione:\n   H Funzione paletta_sort\n              long long paletta_sort(int N,  int V[]);\n        — L’intero N rappresenta il numero di elementi (Ila ordinare.\n        — Il vettore V, indicizzato da 0 a N — 1, contiene la sequenza da ordinare.\n        — La funzione dovra restituire il numero ribaltamenti effettuati per ordinare V, oppure —1 se non\n          c’è modo di ordinare il vettore.\nIl grader chiamera la funzione paletta_sort e ne stampera il valore restituito sul file di output.\nGrader di prova\nNella directory relativa a questo problema è presente una versione semplificata del grader usato durante\nla correzione, che potete usare per testare le vostre soluzioni in locale. 1l grader di esempio legge i dati di\ninput dal file input.txt, chiama le funzioni che dovete implementare e scrive il file output.txt, secondo\nil seguente formato.\nIl file input.txt è composto da due righe, contenenti:\n   .  Riga 1: 'unico intero N.\n   e  Riga 9: i valori Vil overi=0 N   -1"
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        "ocr_text": "   e  0.2:  se il vettore V & ordinabile e restituisci un numero maggiore o uguale a 0 (anche se non\n      corrisponde al  numero minimo di ribaltamenti),  cioè riesci a  distinguere quando il vettore è\n      ordinabile;\n   e  0: altrimenti.\nPer ogni subtask riceverai un punteggio pari al valore del subtask moltiplicato per il peggior punteggio\nottenuto su uno dei suoi test case.\n   .  Subtask 1  [ 5 punti]: Casi d’esempio.\n   .  Subtask 2  [19 punti]: N < 100.\n   .  Subtask 3  [24 punti]: N < 5000.\n   .  Subtask 4  [21 punti]: N < 100000 e R < 100 (oppure V non è ordinabile).\n   .  Subtask 5  [25 punti]: N < 100000.\n   .  Subtask 6  [ 6 punti]: Nessuna limitazione specifica.\nEsempi di input/output\n                                S\n  5      =1\n  20431\n  6\n  230541\nSpiegazione\nNel primo caso di esempio, non ¢ possibile ordinare il vettore dato.\nNel secondo caso di esempio, la soluzione proposta produce la seguente sequenza di ribaltamenti:\n                                [9TaTlpnlslal1]"
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